Re: MOT charging reactor PS

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Jim Lux by way of Terry Fritz <twftesla-at-qwest-dot-net>" <jimlux-at-earthlink-dot-net>

You could, but there is also the "iron loss" to contend with.  Eddy
currents, etc. result in an AC loss.

All in all, it probably doesn't matter very much.

Tesla list wrote:
> 
> Original poster: "Wells Campbell by way of Terry Fritz
<twftesla-at-qwest-dot-net>" <wellscampbell-at-onebox-dot-com>
> 
> Jim lux wrote:
> 
> > The foregoing assumes that the inductor is a pure inductor and has
> > no loss.
> >  If you want to determine the loss, you'll need to a bit of math and
> > use
> > the source voltage (Vs) as well...  Consider the inductor as the sum
> > of
> > some resistance and inductance (Rx + Lx).  The math is left as an exercise
> > for the reader...
> 
> Jim,
> 
> thanks, I'll give it a try...
> 
> As for the loss in the inductor, could you use a constant DC to measure
> the resistance of the inductor without any inductive effects?
> 
> --
> Wells Campbell
> wellscampbell-at-onebox-dot-com - email
> (415) 430-2169 x3756 - voicemail/fax
> 
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