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Re: Dwell time, etc



Original poster: "Gerry  Reynolds" <gerryreynolds@xxxxxxxxxxxxx>

Hi John,

I calculated the dwell time on my 8 inch 1800rpm SRSG with four 1/8" flying electrodes and thought the dwell time was like 3 or 4 times the energy transfer time. This seemed long enough for energy to flow back into the primary and reignite the gap. However, it also seemed like if a breakout occurs, the energy is quickly removed from the secondary so dwell time would not be a problem. Is this correct thinking or did I make an error somewhere??

Gerry R.


Original poster: FutureT@xxxxxxx
After the gap fires, the cap is mostly empty of voltage.  It takes
time for the current to charge the cap to reach enough voltage
to fire across the gap again.  This is similar to how a static
gap quenches, then fires again when the voltage reaches
a high enough level to jump the gap.  In the rotary, by the time
the cap has enough voltage to jump the gap, the electrodes should
have passed out of alignment, so no spark will occur until the
next time the electrodes align.  The uncharged cap is holding
down the voltage during the initial cap charge time because the
cap is large enough in value so it takes enough time to fill.  Imagine a
bucket of water with a small hole drilled two inches away from the
bottom (on the side of the bucket).  This hole represents
the still-aligned electrodes of the
rotary.  If you start filling the bucket using a water hose, the
water will not pour out of the hole right away.  First the bucket
will need to fill to the level of the hole.  But during this time
the electrodes move out of alignment thus "closing" the hole.
Then the bucket can fill completely.

John