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Re: AC wire resistance with proximitry effects
- To: tesla@xxxxxxxxxx
- Subject: Re: AC wire resistance with proximitry effects
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Mon, 10 Oct 2005 11:47:55 -0600
- Delivered-to: testla@pupman.com
- Delivered-to: tesla@pupman.com
- Old-return-path: <vardin@twfpowerelectronics.com>
- Resent-date: Mon, 10 Oct 2005 11:49:20 -0600 (MDT)
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Original poster: "Gerry Reynolds" <gerryreynolds@xxxxxxxxxxxxx>
Hi Bart,
I understand now what you are saying. One thing I might question is
your equation for Q. I dont think this is the right equation for a
series RLC circuit:
The RLC Laplace impedance is sL + R + 1/sC
I(s) = V(s) / sL+R+1/sC
to put in standard form:
I(s)/V(s) = (s/L) / (s^2 + sR/L + 1/LC) = (s/L) / (s^2 + s Wo/Q + Wo^2)
Wo = sqrt (1/LC)
R/L = Wo/Q
Q = WoL/R = sqrt (L/C) / R
Gerry R
Original poster: "Barton B. Anderson" <bartb@xxxxxxxxxxxxxxxx>
First, regarding Ldc. Your right, it's not in the equation for
Fraga, but it is used when predicting Q. Here is what I'm doing, at
least at this time.
ESR = wL/Q
Q = wL/ESR
I am replacing ESR with Fraga's resistance because it is a combined R.