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Re: AC wire resistance with proximitry effects
- To: tesla@xxxxxxxxxx
- Subject: Re: AC wire resistance with proximitry effects
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Mon, 10 Oct 2005 16:30:55 -0600
- Delivered-to: testla@pupman.com
- Delivered-to: tesla@pupman.com
- Old-return-path: <vardin@twfpowerelectronics.com>
- Resent-date: Mon, 10 Oct 2005 16:36:06 -0600 (MDT)
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- Resent-message-id: <wvBmdC.A.N3E.SzuSDB@poodle>
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Original poster: "Malcolm Watts" <m.j.watts@xxxxxxxxxxxx>
On 10 Oct 2005, at 11:47, Tesla list wrote:
> Original poster: "Gerry Reynolds" <gerryreynolds@xxxxxxxxxxxxx>
>
> Hi Bart,
>
> I understand now what you are saying. One thing I might question is
> your equation for Q. I dont think this is the right equation for a
> series RLC circuit:
>
> The RLC Laplace impedance is sL + R + 1/sC
>
> I(s) = V(s) / sL+R+1/sC
>
> to put in standard form:
>
> I(s)/V(s) = (s/L) / (s^2 + sR/L + 1/LC) = (s/L) / (s^2 + s Wo/Q +
> Wo^2)
>
> Wo = sqrt (1/LC)
>
> R/L = Wo/Q
>
> Q = WoL/R = sqrt (L/C) / R
>
> Gerry R
>
>
> >Original poster: "Barton B. Anderson" <bartb@xxxxxxxxxxxxxxxx>
>
> >First, regarding Ldc. Your right, it's not in the equation for
> >Fraga, but it is used when predicting Q. Here is what I'm doing, at
> >least at this time.
> >
> >ESR = wL/Q
> >Q = wL/ESR
> >I am replacing ESR with Fraga's resistance because it is a combined
> >R.
I'm struggling to see a difference apart from Bart defining "R" as
"ESR" which is quite correct.
??
Malcolm
>
>
>
>
>