Re[2]: MOT current limiting shunts

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: Mike Poulton <mpoulton-at-mtptech-dot-com> 

Tesla list Wrote:
 > Original poster: "Sean Taylor" <sstaylor-at-uiuc.edu>
 > You have to divide by the turns ratio SQUARED - the equivalent resistance of
 > something on the other side of the transformer is scaled by the turns ratio
 > squared.  Say you have a 120/12V transformer, N = 10, and a 12 ohm load on
 > the secondary.  The secondary draws 1 amp, and the primary draws 1/10 amp.
 > Requivalent = 120/(1/10) = 1200 ohms, or 12*(10^2).

Thanks!  That makes perfect sense, but I had never thought about it.

-------------------------------------------------
Mike Poulton
MTP Technologies
mpoulton-at-mtptech-dot-com
KC0LLX (70cm AM ATV, 33cm/12cm FM ATV, Omaha, NE)