Re: Re[2]: MOT current limiting shunts

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Hydrogen18" <hydrogen18-at-hydrogen18-dot-com> 

I understand what you are saying.

----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Monday, January 12, 2004 12:41 PM
Subject: Re[2]: MOT current limiting shunts


 > Original poster: Mike Poulton <mpoulton-at-mtptech-dot-com>
 >
 >  > Original poster: "Hydrogen18" <hydrogen18-at-hydrogen18-dot-com>
 >  > For example, say we have a 240 VAC winding that draws 4 amps when the
 > secondary
 >  > is shorted(secondary number of turns not important in this example). If
we
 >  > divide volts / amperes = impedance we get 240 / 4 = 60 ohms. I'm pretty
sure
 >  > that is the correct way to do that.
 >
 > What you just measured there is the *impedance* of the transformer,
 > which includes the resistance of the primary and secondary, and the
 > leakage inductance, all in series.  To measure the actual resistance
 > of a winding, apply a *DC* voltage and measure the current through it
 > (or vice versa).
 >
 > -------------------------------------------------
 > Mike Poulton
 > MTP Technologies
 > mpoulton-at-mtptech-dot-com
 > KC0LLX (70cm AM ATV, 33cm/12cm FM ATV, Omaha, NE)
 >
 >
 >