Re: Wire-wound resistors as dummy test load

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "marlow by way of Terry Fritz <twftesla-at-qwest-dot-net>" <marlow-at-rconnect-dot-com>

A wire wound resistor is still an inductor, what effect does adding that
inductance have on things.


----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Thursday, October 03, 2002 1:01 PM
Subject: Re: Wire-wound resistors as dummy test load


> Original poster: "Edward Wingate by way of Terry Fritz
<twftesla-at-qwest-dot-net>" <ewing7-at-rochester.rr-dot-com>
>
> Tesla list wrote:
> >
> > Original poster: "Peter Komen by way of Terry Fritz
<twftesla-at-qwest-dot-net>"
> <pkomen-at-zianet-dot-com>
> >
> > Ed,
> >
> > Well, let's look at this.
> > 200 Ohm 200 watt resister to dissipate 200 Watts will need a current
through
> > it of 1 Amp.  Hook 4 in series and run a current of 1 Amp through them,
and
> > the dissipation for each resister is still I^2 * R or 200 Watts.  The
total
> > dissipation is 800 watts for the 4 in series.  Figure it 2 ways 4 * 200
> > Watts = 800 Watts or 1 Amp^2 * 800 Ohms = 800 Watts.
> >
> > If the resisters are different resistances are the power dissipated in
each
> > will not be equal, but if certain things are known about the circuit,
the
> > power dissipated in each resister can be calculated.  Suppose that we
have
> > two resisters in series: a 1-Ohm 2-Watt resister and a 200-Ohm 200-Watt
> > resister.  If 201V is applied across the two resisters, 1 Amp will flow
and
> > the resisters will dissipate 201 Watts; 1 Watt in  the 1-Ohm resister
and
> > 200 Watts in the 200 Watt resister..
> >
> > Could explain your reasoning?
> >
> > Regards,
> >
> > Pete Komen
>
> Pete,
>
> Apparently, not very well.
>
> Please see Dave Specks' reply, he said it better than I can.
>
> Ed Wingate RATCB
>
>
>
>