Re: Wire-wound resistors as dummy test load

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Edward Wingate by way of Terry Fritz <twftesla-at-qwest-dot-net>" <ewing7-at-rochester.rr-dot-com>

Tesla list wrote:
> 
> Original poster: "Peter Komen by way of Terry Fritz <twftesla-at-qwest-dot-net>"
<pkomen-at-zianet-dot-com>
> 
> Ed,
> 
> Well, let's look at this.
> 200 Ohm 200 watt resister to dissipate 200 Watts will need a current through
> it of 1 Amp.  Hook 4 in series and run a current of 1 Amp through them, and
> the dissipation for each resister is still I^2 * R or 200 Watts.  The total
> dissipation is 800 watts for the 4 in series.  Figure it 2 ways 4 * 200
> Watts = 800 Watts or 1 Amp^2 * 800 Ohms = 800 Watts.
> 
> If the resisters are different resistances are the power dissipated in each
> will not be equal, but if certain things are known about the circuit, the
> power dissipated in each resister can be calculated.  Suppose that we have
> two resisters in series: a 1-Ohm 2-Watt resister and a 200-Ohm 200-Watt
> resister.  If 201V is applied across the two resisters, 1 Amp will flow and
> the resisters will dissipate 201 Watts; 1 Watt in  the 1-Ohm resister and
> 200 Watts in the 200 Watt resister..
> 
> Could explain your reasoning?
> 
> Regards,
> 
> Pete Komen

Pete,

Apparently, not very well.

Please see Dave Specks' reply, he said it better than I can.

Ed Wingate RATCB