[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

*To*: tesla-at-pupman-dot-com*Subject*: Re: ballast formula*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Thu, 22 Feb 2001 18:08:48 -0700*Resent-Date*: Thu, 22 Feb 2001 18:12:48 -0700*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <zv7AuD.A.61D.2jbl6-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "James T by way of Terry Fritz <twftesla-at-uswest-dot-net>" <jamest2000-at-att-dot-net> Hi Deano, Thanks for the response. That is just what I was looking for. I think i need those drawings to figure out the mean length. Whenever you get a chance to scan those pages would be great. There should be a clickable email next: mailto:jamest2000-at-att-dot-net I think the MU(permaebility) should be around 60,000. Does that sound right? Thanks James Tesla list wrote: > Original poster: "David Dean by way of Terry Fritz <twftesla-at-uswest-dot-net>" <deano-at-corridor-dot-net> > Hi James, > I have an old text book with some of that stuff in it. It says: > L = N^2*mu*A/10^8*l > (L equals N squared mu A over ten to the eighth l) > where L is in henries, > and N = number of turns > mu = permeability of core (in English units) > A = area of core in square inches > l = mean length of core in inches > The mean length would be {twice the length of the center leg (with the I > part on there) plus twice half the width of the core} plus [the perimeter of > one window} / 2. > Trying to draw pictures with words is not my strong point. If you want, I > can scan the pages and email them to you. > > later > deano

- Prev by Date:
**Insulator components** - Next by Date:
**Re: VTTC first sound :-)** - Prev by thread:
**RE: ballast formula** - Next by thread:
**Re: ballast formula** - Index(es):