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*To*: tesla-at-pupman-dot-com*Subject*: Re: [Fwd: Spark gap not firing]*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Sat, 10 Feb 2001 19:56:14 -0700*Resent-Date*: Sat, 10 Feb 2001 20:03:40 -0700*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <gv5TC.A.V8E.IEgh6-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Luc by way of Terry Fritz <twftesla-at-uswest-dot-net>" <ludev-at-videotron.ca> Hi Ed, Terry, list Tx guy for your help. Just to verified if I understand well: If I want a cutoff frequency of 50 KHz and I use a resistance of 2 Kohms I need a cap of 1.59 nF. If I use less resistance and more capacitance for the same value in the equation is the curve: frequency to db attenuation will be stepper ? If my coil have a resonant F of 100 KHz is this filter good or I'll need a cutoff F lower . Luc Benard Tesla list wrote: > Original poster: "Ed Phillips by way of Terry Fritz <twftesla-at-uswest-dot-net>" <evp-at-pacbell-dot-net> > > > > The expression for the half-power cutoff frequency of a low pass RC > filter is simply > > Fc = 1/(2*pi*R*C) > > where Fc is in Hz at which the output voltage/input voltage ratio is > 0.707 [1/sqrt(2)] , R is in ohms, and C is in farads. This applies to > the simplified case of a filter between a zero-impedance source and an > infinite impedance load. In the case of such a filter inserted between a > TC primary circuit and a transformer, things may not be quite so simple. > > Ed

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