RE: Geek Group Caps, calcualting for a MMC

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Pete Komen by way of Terry Fritz <twftesla-at-uswest-dot-net>" <pkomen-at-zianet-dot-com>

Jonathan,
For a number of the same caps in series, divide the capacitance of one cap
by the number of caps.

2* * = .075uf/ 4kv,  3* = .05uf/6kv,  4*= .0375/8kv,  5*= .03/10kv

I am close to first light on my first coil.

Pete

-----Original Message-----
From: Tesla list [mailto:tesla-at-pupman-dot-com]
Sent: Thursday, April 19, 2001 8:21 AM
To: tesla-at-pupman-dot-com
Subject: Geek Group Caps, calcualting for a MMC

Original poster: "jpeakall by way of Terry Fritz <twftesla-at-uswest-dot-net>"
<jpeakall-at-mcn-dot-org>

Howdy,

I could use a clue. Is this how gagning up caps works?

Assuming the GG caps (.15 uf, 2kv)

2* = .075uf/ 4kv,  3* = .0375uf/6kv,  4*= .0187/8kv

What I mostly want to know is if I have the voltage ratings right.

Thanks for bearing with the mathematically challanged.

Jonathan