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RE: Ok.. where am I going wrong

Ok.. since this is the third person to make this comment...
The resitor is not there for the majority of the current limiting.
It is only meant to smooth the surges from the purely inductive
system. Each element in the system, as they are all in series,
*must* see the total current passing through. This is the whole
reason limiting works anyway. I had just hoped to take advantage
of the fact that this smoothing resistor would have voltage drop
across it proportinal to the current passing through it. I am just
trying to find out why my wires are not getting warm, and the fuses
are not blowing, yet my meter says I am exceeding my circut capacity
by 50%. I have gotten some pointers to the problem, that I have not
had a chance to test yet.

Michael Baumann
Coiler, Homebrewer, Nerd. mycroft-at-access1-dot-net


> -----Original Message-----
> From: Tesla List [mailto:tesla-at-pupman-dot-com]
> Sent: Saturday, November 14, 1998 5:18 PM
> To: tesla-at-pupman-dot-com
> Subject: Re: Ok.. where am I going wrong
>
>
> Original Poster: "Barton B. Anderson" <mopar-at-uswest-dot-net>
>
> Michael,
> For current flow, you must have both sides of the AC joined together. The
> current flows back and forth from one leg to the other through the
> components in
> your circuit. The components are all in series forming a circuit
> "loop". The
> 0.4ohm resistor is just one component in the loop. In order to "calculate"
> current flow in the total loop, you must account for all
> resistance including
> the resistance and reactance of the ballast, pig, etc... If your 0.4 ohm
> resistor was the only thing in the circuit, then you would draw 40+ amps
> across
> the resistor and blow your fuses. Obviously, the current is being limited
> by the
> other components in the circuit.
>
> Hope this helps,
> Bart
>
> Tesla List wrote:
>
> > Original Poster: "Coiler" <mycroft-at-access1-dot-net>
> >
> > I just finished wiring up my pig-training facility. This means the
> > welder, 0.4 ohm resistor and 240V feed. I had thought to calibrate the
> > switch settings on the welder to KVA numbers by taking voltage readings
> > across the resistor. The infamous V=IR business. Only.. it didn't work.
> > Or I don't think it did. At one point, I measured a drop of
> 17V. This works
> > out to roughly 42 amps. This cannot be. I have 30A fast blow
> fuses in the
> > line
> > and I suspect that they would fry in short order at almost 50% overload.
> > Therefor, there must be someting I am missing. I assume it is
> related to the
> > fact that this is AC.
> > Could someone help me out here? Tell me where I goofed.
> >
> > Michael Baumann
> > Coiler, Homebrewer, Nerd. mycroft-at-access1-dot-net
>
>
>