Re: Continued Problems (fwd)

---------- Forwarded message ----------
Date: Tue, 12 May 1998 09:06:19 -0700
From: Jim Lux <jimlux-at-earthlink-dot-net>
To: Tesla List <tesla-at-pupman-dot-com>
Subject: Re: Continued Problems (fwd)

> ----------
> From:  fxphoto [SMTP:fxphoto-at-centuryinter-dot-net]
> Sent:  Monday, May 11, 1998 2:57 PM
> To:  Tesla List
> Subject:  Re: Continued Problems (fwd)
> Hi Malcom,
>  Thanks for the info. If I am understanding you properly then if I were
> add a 1H coil to the primary side of a 100 to 1 ratio transformer it
> show up on the secondary side as an additional 100H inductance.
>  And if I were to put two 100 mH chokes on the secondary side they would
> reflect back on the primary of the same transformer as 2mH.
>                                Thanks again for helping me to understand
>                                 Bill Turbett

Actually, the value of the impedance reflects as the SQUARE of the turns
ratio. Example: use a 1:100 transformer. Assuming the primary has 1 amp at
1 volt going in (i.e. an impedance of 1 ohm), the secondary has 100 Volts
at .01 Amps coming out, which corresponds to a load impedance of 10K.