Re: Toroid Design .
Isn't the charge zero on the inside of the upper terminal during VDG
operation? How can there be an "up hill" effect for the charge on the belt?
I would consider it a "down hill" effect.
The work to put the charge (100% eff) on the outside of the terminal is
W = Q x V joules per coulomb
Have you found an equation to relate this work to the motor that would
indicate the motor slows down as the voltage on the outside of the terminal
At 08:17 PM 12/25/98 -0700, you wrote:
>Original Poster: Ed Phillips <evp-at-pacbell-dot-net>
>" Jim -
> This is the first time I have heard that the Van deGraaf motor slows
>because of the upper electrode voltage. I thought the transfer of
>from the belt to the inside of the sphere was because the potential on
>inside of the sphere was less than on the belt.
> John Couture"
> The motor slows down (if it is of marginal power, at least) because, as
>the upper terminal voltage increases, more work is being done to move
>the charges "up hill". Real effect!