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Re: [TCML] Copper wire resistance calculation ?

Sorry Chris,
I meant 0.1 or so. Typo
Phillip.

 
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72 Tinwell Road, Stamford, Lincs PE9 2SD 

Tel: 01780 753008



----- Original Message ----
From: Phillip Strauss <pstrauss1947@xxxxxxxxx>
To: Tesla Coil Mailing List <tesla@xxxxxxxxxx>
Sent: Wednesday, September 10, 2008 4:43:56 PM
Subject: Re: [TCML] Copper wire resistance calculation ?

Hi Chris,
Forgot, those figures assume a k of 0.13 but when I build the coil I will probably use a lower coupling perhaps up to 0.15.
Phillip.


_____________________________________________________________________________

72 Tinwell Road, Stamford, Lincs PE9 2SD 

Tel: 01780 753008



----- Original Message ----
From: Chris Swinson <list@xxxxxxxxxxxxxxxxxxxxxxxxx>
To: Tesla Coil Mailing List <tesla@xxxxxxxxxx>
Sent: Wednesday, September 10, 2008 4:04:07 PM
Subject: Re: [TCML] Copper wire resistance calculation ?


----- Original Message ----- 
From: "jimlux" <jimlux@xxxxxxxxxxxxx>
To: "Tesla Coil Mailing List" <tesla@xxxxxxxxxx>
Sent: Wednesday, September 10, 2008 2:36 PM
Subject: Re: [TCML] Copper wire resistance calculation ?


> Chris Swinson wrote:
>> I am trying to calculate from lengh, dia, in inches to resistance.
>>
>> I have
>>
>> Rho = 0.0000000174 / 39.3700787 ( resistance per inch)
>>
>> (4*WL*Rho)  /  (Math.sqrt(WD)*PI)
>>
>> WL=wire length in inches
>> WD = Wire dia in inches.
>>
>> Can't seem to get it to come out with any logical results. Could just be
>> how I set it out, or its convertion cross sectional area wrong or
>> something ?
>>
>
> Don't you want the square of the diameter, not the square root?  i.e.
> you want length/area * rho


Ah!

Rho = 0.0000000174 / 39.3700787 // resistivity of copper is default per 
meter, convert to inches
area = WD*WD
RESULT = WL / area * Rho

I tried this in relation to the JavaTC demo coil, that gave 27ohms, though 
my figure comes out 0.015620142575432545 ?

chris


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