C = 0.2248*k*A*(N-1)/(d*x) (in pF)
where
k = Dielectric constant (1.0006 for air)
A = Effective plate area in square inches (length x width)
N = Number of conductive plates (3 for a rolled cap)
d = individual dielectric film thickness (.03937" in this case)
x = number of stacked sheets of dielectric between plates (1 in
this case)
So if the effective capacitance is as 1/4 of that of a single
turn-to-single-turn coil, using the above I calculate around 200pF. Still
I bet in real
life it's much less than that!
I think Chris is looking at about 6.4nF for the ribbon primary.
If we could get that much capacitance out of reasonable ribbon primaries,
we
wouldn't bother with primary tank caps!