Here is a model coil - a ribbon primary, and some results.
Plane of ribbon: vertical;
Inner diam: 55.88 cm;
Turns: 4;
Pitch: 0.18128 cm;
Outer diam: 55.88 + 0.18128 * 4 * 2 cm;
Ribbon thickness: 0.1 cm;
Ribbon width: 5.08 cm;
The coil is modeled using a number of equally spaced filaments
each having a diameter equal to that of the ribbon thickness.
filaments L uH
1 29.46
2 19.87
3 18.29
4 17.74
5 17.48
6 17.34
7 17.25
8 17.20
9 17.16
10 17.13
12 17.10
14 17.08
18 17.06
As a by-product we get the current distribution across the
width of the ribbon. For 18 filaments numbered 1..18, the
percentage current down each filament is:-
1: 18.33
2: 5.52
3: 4.57
4: 4.16
5: 3.75
6: 3.54
7: 3.46
8: 3.37
9: 3.30
10: 3.30
11: 3.37
12: 3.46
13: 3.54
14: 3.75
15: 4.16
16: 4.57
17: 5.52
18: 18.33
The current distribution is symmetric, but that's only because
this is a vertical ribbon.
Having modeled the ribbon coil in this way, there is then the
question of how to represent the coil during calculations of
M with other coils. I was thinking of representing it as a
single filament, the position of which corresponds to the
'center of mass' of the current distribution. Question is,
would that be sufficient for typical primary-secondary M
calculations?
--
Paul Nicholson
--
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