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Re: calculations of capacitance (IMPORTANCE)



Original poster: "Joe Smith" <proffessor@xxxxxxxxxxx>

These messages are like pure gold to a 61 yoqr old highschool dropout
trying
to learn algebra.
a great big THANKS!!!
joe.


On Wed, 21 Feb 2007 01:35:57 -0700, "Tesla list" <tesla@xxxxxxxxxx>
said:
> Original poster: "James Howells" <james@xxxxxxxxxxxxxxxxxxxxxxx>
>
> Thanks .... I remember now you reminded me .... Its been about 45
> years since I did it at school! ...............I put it in a spread
> sheet in the end and confirmed that it was .16  Thanks so much for your
> reply
>
> James ...........may be let out of the Home for the bewildered for a
> few hours to day lol
> www.SpamJab.com {UgzndUInruKjv2Cy9r}
>
> ----- Original Message ----- From: "Tesla list" <tesla@xxxxxxxxxx>
> To: <tesla@xxxxxxxxxx>
> Sent: Wednesday, February 21, 2007 2:52 AM
> Subject: Re: calculations of capacitance
>
>
> >Original poster: Frank <fxrays@xxxxxxxxxx>
> >
> >Hi,
> >Basic algebra, you have to have the denominators the same to add,
> >you just cannot add top and bottoms.
> >
> >OK, you have for the denominator;
> >
> >6/1n + 1/10n = 60/10n + 1/10n = 61/10n. Inverting this for the final
> >answer is 10n/61 = 0.16 n which is correct for your first answer.
> >
> >You cannot just add top and bottoms in fractions, you have to make
> >the bottoms all the same values first before adding and then the
> >bottoms do not add, just the tops!
> >
> >In your example too, the final voltage rating is 6 X 6KV + 1 X 2KV + 38 KV.
> >
> >Frank
> >
> >At 05:12 PM 2/19/2007 -0700, you wrote:
> >>Original poster: "James Howells" <james@xxxxxxxxxxxxxxxxxxxxxxx>
> >>
> >>I don't know why but I have got myself completely flummoxed trying
> >>to work out a primary cap from the components I have at hand
> >>
> >>I don't have enough capacitors of the same value to do a normal MMC
> >>and want to mix and match what I have got But I have got myself in
> >>a real error loop
> >>
> >>
> >>Say I have 6 caps at   1nF and voltage rated at  6KV
> >>I put them in series then add( in series) a 10nF capacitor but only 2KV
> >>I know I don't get 32 Kv rating ..but what do I get ?
> >>
> >>I have worked out the total capacity  1/ total =   1/c1+ 1/c2+ 1/c3
> >>.............
> >>and got two different answers
> >>
> >>1/10+ 1/1 ..................1/1       = 1/    .1 +
> >>6      =  6.1    invert for total cap =    .16nF
> >>
> >>
> >>OR
> >>                    adding all the numerators and denominators  you
> >> get 7/16   =  invert to give TOTAL =  2.28nF
> >>
> >>I really have confused my self
> >>
> >>
> >>Replies to
> >>James
> >>The Brighton Home for  Bewildered Coilers
> >>Brighton
> >>Sussex
> >>England  :)))))))
> >>
> >>
> >>
> >>
> >><http://www.SpamJab.com>www.SpamJab.com {UgzndUInruKjv2Cy9r}
> >>
> >>
> >>
> >>
> >
> >
> >
>
>
>
>
>
--
  Joe Smith
  proffessor@xxxxxxxxxxx

--
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