Re: Wire length theory (fwd)

["Tesla list" <tesla@xxxxxxxxxx>]

Moderated and approved by: Gerry Reynolds <greynolds@xxxxxxxxxx>



---------- Forwarded message ----------
Date: Tue, 26 Dec 2006 21:24:34 -0800
From: Barton B. Anderson <bartb@xxxxxxxxxxxxxxxx>
To: Tesla list <tesla@xxxxxxxxxx>
Subject: Re: Wire length theory (fwd)

Hi Jared,

Thanks for sending. I'll take some time on this and get back to you as 
time permits.

Take care,
Bart

Tesla list wrote:

>Moderated and approved by: Gerry Reynolds <greynolds@xxxxxxxxxx>
>
>
>
>---------- Forwarded message ----------
>Date: Sun, 24 Dec 2006 22:38:25 -0500
>From: Jared Dwarshuis <jdwarshuis@xxxxxxxxx>
>To: Pupman <tesla@xxxxxxxxxx>
>Subject: Wire length theory
>
>Hi: Bart
>
>
>
>From: Jared Dwarshuis
>
>
>
>The framework of our model as requested:
>
>
>
>(1)   Maxwells equations must be satisfied.
>
>
>
>(2)   Maxwells prediction that E.M. waves travel at the speed of light must
>be satisfied.
>
>
>
>(3)   Standing waves are the result of forward and reverse waves of equal
>amplitude.
>
>
>
>(4)   Since voltage A to B = L di/dt.  Standing waves within an inductor
>must partition the inductor so that it's frequency components are contained
>within the quarter wavelength region. The sum of inductive energy storage
>equals the sum of these quarter wavelength regions.
>
>
>
>(5)   We can take the standard form for inductance (in the ideal) and write
>this as:
>
>       L = u (wire length)sqrd / 4pi H
>
>
>
>(6) We must satisfy the expression:   C = frequency x wavelength
>
>
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>(7) We must reconcile the disparity between frequency = C/ wavelength
>and  frequency
>= 1/ 2pi sqrt(LC)  and modify both equations to include the features of
>nodality guaranteed by the mathematics of standing wave resonance.
>
>
>
>(8) We partition Inductance as follows:
>
>L = u ( wire length/2n) 2n/H
>
>where n = 1/2, 2/2, 3/2 ��
>
>
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>(9) We partition the equation C = freq.x  wavelength with:
>
>Freq. = n/2 C/(wire length)
>
> where n = 1/2, 2/2, 3/2 ��
>
>
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>(10) We set these expressions equal:
>
>n/2 C/wire = 1/2pi sqrt( [u (wire/2n)sqrd 2n/H ] [capacitance] )
>
>where n = 1/2, 2/2, 3/2 ��
>
>
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>End.
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>  
>