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*To*: tesla@xxxxxxxxxx*Subject*: Units of electricity*From*: "Tesla list" <tesla@xxxxxxxxxx>*Date*: Thu, 24 Aug 2006 16:31:50 -0600*Delivered-to*: testla@xxxxxxxxxx*Delivered-to*: tesla@xxxxxxxxxx*Old-return-path*: <vardan01@xxxxxxxxxxxxxxxxxxxxxxx>*Resent-date*: Thu, 24 Aug 2006 16:31:58 -0600 (MDT)*Resent-from*: tesla@xxxxxxxxxx*Resent-message-id*: <JmdRJXhrkhO.A.o0C.eji7EB@chip1>*Resent-sender*: tesla-request@xxxxxxxxxx

Original poster: Jared E Dwarshuis <jdwarshui@xxxxxxxxx> Hi Jared, Didn't Tesla himself use the old mechanical analogies for tuned circuit, i.e. likening them to a mass on spring with friction, referring to things like impedance as inertia, or am i mistaken here? I have often noted the similarities between mechanical and electrical systems. Take for example the energy stored in a capacitor E=1/2CV^2 (c=capacitance, v=voltage) and then look at the energy in a moving object E=1/2MV^2 (m=mass, v=velocity). I agree with you, but it would be nice to see these things worked out from first principles. Thanks Chris R ?????????????????????????????????. Hi Chris: I Don?t know much about Tesla, just the stuff in biographies. The energy stored in a capacitor, ½ CVsqrd comes out as: E = ½ ss/m (As/m)sqrd x (kg m /ss)sqrd x ( m/As)sqrd The (As/m)sqrd and (m/As)sqrd cancel leaving: Energy = kg mm/ss E = ½ L Isqrd also works the same way. You really want to group inductance with kinetic energy and capacitance with potential energy. So capacitance is associated with ½ k Xsqrd and inductance is associated with ½ M Vel.sqrd (inductors work by having charge in motion!) Voltage is in units of joules/coulomb so we can write: V =Force x (meters/ coulombs) Since a coulomb is an amp second we can write: V = Force x (m/As) q is in coulombs so we can write q = As : We certainly can multiply meters by both the numerator and denominator such that q = m ( As/m) Now we can write current as m/s x (As/m) and we can write dI/dt as: m/ss x (As/m) Since V = -L dI/dt we are guaranteed that inductance can be written as: L = kg x (m/As)sqrd Now lets write V = -L di/dt [Force] x (m/As) = [kg] x (m/As)sqrd x [m/ss] x (As/m) After canceling units of (m/As) on both sides. We get: Force = Mass x Acceleration Sincerely: Jared Dwarshuis

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