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Re: LC and Misc.
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- Subject: Re: LC and Misc.
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Sat, 30 Jul 2005 21:51:10 -0600
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Original poster: "Gerry Reynolds" <gerryreynolds@xxxxxxxxxxxxx>
Hi Jared,
Original poster: Jared E Dwarshuis <jdwarshui@xxxxxxxxx>
From: Jared Dwarshuis
Consider a given length of wire and a target LC frequency. We could
wind a stubby inductor or a skinny inductor.
If we wind a skinny inductor, our inductance will be very low and our
top end capacitance will be rather large.
If we wind a stubby inductor, our inductance will be high, but our top
end capacitance will be very low.
OK, if we use the simplified equation L=uo*N*A/h,
where uo = permibility of free space
N = number of turns,
A = cross sectional area of coil
h = height of coil
assume close wound,
and substitute N= Wl/(2*pi*r) A = pi*r^2, and h = N*Wd
where Wl = wire length
Wd = wire diameter
r = radius of coil
we get: L = uo * Wl * r / (2*Wd). If Wd and Wl are constant, the
stubby inductor will have more inductance as compared to the skinny one.
A stubby inductor has a very high self capacitance. In theory you
could make a coil with no top end at all. (maybe someone out there has
done so?)
If we take two spheres at the same voltage (one with small radius and
the other with larger radius). The E field on the smaller one will
be greater at the surface (due to smaller ROC) and drop off sooner
(smaller reach) as one moves away from the sphere. The smaller
sphere will also require a smaller charge to reach the same
voltage. So, I guess the self capacitance of the coil is
proportional toWl and the radius of the coil (first order affects maybe).
I think, like you say, one could use that length of wire and choose
the radius where the self capacitance and the inductance gives the
specified frequency. If the specified freqency was achieved by self
capacitance only, I think, performance would suffer greatly since not
all of the self capacitance is available to support streamer growth
on a TC discharge and without a "real" top load, breakout would be at
a lower voltage and the E field "reach" would not be as great. But
then again, I'm not sure of your context nor your point.
Gerry R.
Dr. Resonance has, in the past, posted information on the number of
turns and H/D ratios. His guidelines are based on a lot of
experience.