Original poster: "Barton B. Anderson" <bartb@xxxxxxxxxxxxxxxx> Hi MalcolmThanks for taking all the pictures. They are certainly a great help. The primary is my #1 concern. Don't lay the primary tubing into those wooden runner notches, not even with varnish on the form. You "will" eventually, and soon, arc into the runners and carbon track a distance through the wood. I use wooden forms myself, but, I "learned" to add a distance between the wood and the tubing to prevent just this problem. Wood is great for cost and machinability, as long as you adhere to high voltage physics. I use plexiglas runners between my wooden runners and the actual coil. On some other primary's, I've used an actual plastic cylindrical standoff (approx. 1/4 inch from primary to wood).
Your runners look "prepared" for the tubing to just lay down and set inside the notches. I would recommend letting the notches serve as the "position point" for the tubing, but find a pliable insulator to cut to width and length of the runners which you can keep between the windings and runners (at least 1/8 inch thickness).
Just for reference, I've caused a 4 inch length carbon track in G10 disc material (everything is conductive when conditions are right). And for some reason, we coilers always seem to find those conditions.
Best of luck, Bart PS. If you need any explanation of Javatc, just contact me offlist. Tesla list wrote:
Original poster: "MalcolmTesla" <tesla@xxxxxxxxxxxxx> ----- Original Message ----- From: "Tesla list" <tesla@xxxxxxxxxx> To: <tesla@xxxxxxxxxx> Sent: Tuesday, December 13, 2005 7:29 PM > Original poster: Terry Fritz <vardin@xxxxxxxxxxxxxxxxxxxxxxx> > > Hi, > > You should start thinking about "tuning". The frequency of the > primary circuit needs to be tuned to the same frequency as the > secondary circuit. Now is a good time to get a rough idea of the > tuning to be sure you won't end up with a coil that will not > tune. So it is time to do the math or let Bart's program do it for you... > > We know that primary capacitance is 8.33nF. From the details you > give below, we can calculate the maximum inductance of the primary coil. > > Lf = (N x R)^2 / (8 x R + 11 x W) > Lf = (7.5 x 6)^2 / (8 x 6 +11 x 6) = 17.8uH > > The frequency is: > > Fo = 1 / (2 x pi x SQRT(L x C)) msnip....