Re: tungsten carbide magnetic?

• To: tesla@xxxxxxxxxx
• Subject: Re: tungsten carbide magnetic?
• From: "Tesla list" <tesla@xxxxxxxxxx>
• Date: Sat, 09 Apr 2005 12:28:31 -0600
• Delivered-to: chip@pupman.com
• Delivered-to: tesla@pupman.com
• Old-return-path: <teslalist@twfpowerelectronics.com>
• Resent-date: Sat, 9 Apr 2005 12:29:32 -0600 (MDT)
• Resent-from: tesla@xxxxxxxxxx
• Resent-message-id: <7hOHND.A.ukD.37BWCB@poodle>
• Resent-sender: tesla-request@xxxxxxxxxx

`Original poster: BunnyKiller <bunikllr@xxxxxxx>`

`Hey Gerry...`

sorry for being so directive towards David and not the list :)
Im running 2 14.4 KVAC piggies in series for 28.8KVAC + ( im using variacs to go beyond28.8 up to approx. 30KVAC total output) the 280VAC input is drawing 65 A for an estimated 18KW ( roughly) on a full power run.... so in effect this gives one an idea on how much power is being dissapated thru the gaps ( not even to consider the Peak wattage at discharge of gap conduction... ) ruff estimate at .014mF 30KV = 6.30J and at 120BPS should equal 755W per pop
thats alot of heat... :) the doubling of diameter of the rod increases the power handling capacity squared...

`Scot D`

`Tesla list wrote:`

`Original poster: "Gerald  Reynolds" <gerryreynolds@xxxxxxxxxxxxx>`

`Original poster: BunnyKiller <bunikllr@xxxxxxx>`

but do you need that extra diameter? I am using 1/8" dia pure welding tungsten no thorium ( and you know what power Im dealing with ;) ...

I'm afraid I dont know your power. What is the max power for 1/8" pure tungsten, if I may ask? (well heat sinked). Also power levels for 1/4 and 3/8 rod if you know them.

`Gerry R.`