RE: can so please double check my math for me

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Phil Chalk" <phil-at-apsecurity-dot-com.au> 



G'day Jimbo,


3" diameter = 1.5" radius (r)

Circumference = 2 * Pi * r   = length of 1 turn.

(Actually result is slightly low, as effective diameter = former
diameter + 1x wire diameter.  For 16AWG, effective diameter ~ 3.05",
approx 1.6% larger)

So, One turn is approx 2 * Pi * 1.5"  = approx 9.582" per turn.


#16 wire diameter ~ 0.051".

58" / 0.051"  = 1137.  So 58" winding length gives approx (slightly less
than) 1137 turns.


1137 turns x 9.582"/turn  = 908 feet.

BINGO !


That said a 58" long x 3" dia. Coil is one very long, skinny coil.
Aspect ratio is nearly 20.  Pretty uncommon 'round here'.

Cheers,

Phil Chalk.


-----Original Message-----
From: Tesla list [mailto:tesla-at-pupman-dot-com]
Sent: Thursday, 27 May 2004 9:44 AM
To: tesla-at-pupman-dot-com
Subject: can so please double check my math for me

Original poster: Jimbo07031982-at-aol-dot-com

i figure i am going to need a little over 900 feet of 16 awg wire to
cover
a 58 inch coil for that is 3 inch in diameter that seems like a whole
lot
to me and math has always been my weak point and i think i might of
goofed
something some where's thank you all for you precise time jimbo