[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: Charge stored in Dielectric? Not really - MISCONCEPTION
Original poster: robert & june heidlebaugh <rheidlebaugh-at-desertgate-dot-com>
Just an added thought. In Oil you have added a second high dialectric with
active browniun movement to desperse and discharge the voltage charge. I
question the validity of your conclusion. In air with solid components no
large movement is taking place, only a local movement within the dialectric
surface this preventing the stored charge from being neutralized. An example
is the formation of a lectric where the dialectric is charged as a liquid
(wax) and then cooled to a solid before removing the charge voltage. The
charge is stored as a perminant electrostatic charge like an " electrostatic
magnet" in effect.
Robert H
--
> From: "Tesla list" <tesla-at-pupman-dot-com>
> Date: Fri, 23 Jan 2004 20:12:56 -0700
> To: tesla-at-pupman-dot-com
> Subject: Charge stored in Dielectric? Not really - MISCONCEPTION
> Resent-From: tesla-at-pupman-dot-com
> Resent-Date: Fri, 23 Jan 2004 20:18:47 -0700
>
> Original poster: dhmccauley-at-spacecatlighting-dot-com
>
>> Original poster: "Dr. Resonance" <resonance-at-jvlnet-dot-com>
>>
>>
>> A classic capacitor physics experiment. Charge a Leyden jar. Remove the
>> plates completely and short them both together and to ground. Reassemble
>> the jar and it delivers it's normal spark. Charge is stored in the
>> dielectric. The effect of the plates are completely eliminated in this
>> experiment.
>>
>> Dr. Resonance
>
> Actually, I've been doing a lot of research into this since I last saw this
> effect demonstrated at the Rochester Teslathon and have found this to be a
> misconception.
> I've also tried of few of my own experiments to verify this and to see what
> was really going on.
>
> In the demonstration I saw, a capacitor comprised of a thin dielectric
> separated by two flat aluminum plates was charged via a small flyback supply
> to about 10-20kV. The charging
> supply was removed and then the capacitor carefully disassembled. The
> dielectric was removed and passed around the room for all to touch, etc...
> and then the capacitor was
> re-assembled. Upon re-assembling the capacitor, you could once again draw a
> big arc of it proving that the charge of the capacitor was still there and
> it is concluded that
> the dielectric stores the charge all along. To further prove this, the
> dielectric could be rolled up, mailed across the country, and assembled in a
> separate set of plates and once together,
> again an arc could be reproduced again proving that the charge is indeed
> charged in the dielectric.
>
> However, this is not correct.
>
> What is actually happening is quite complex. When the two plates of the
> capacitor are moved apart, the total capacitance of the plate capacitor
> drops and as a result, the potential
> difference between the plates increases to enormous levels. Because of the
> physical arrangement of the two plates, this potential cannot increase
> infinitely and instead it forms
> corona along the outer metal edges of the plates and leaks the excess charge
> into the surrounding air. This corona (which can be heard during this
> experiment) then allows
> opposite electrical charges to be "sprayed" or "painted" onto both sides of
> the internal dielectric material. So when you dissassemble this capacitor,
> this corona effect transfers a
> large percentage of the separated charges from the aluminum plates onto the
> dielectric surfaces. The energy is still there, but its stored as a field
> in the dielectric material.
>
> To further disprove this misconception, i did the two experiments which were
> recommended to me by an old timer friend of mine.
> With a similar set-up, I did the following experiments.
>
> 1. I repeated the standard experiment. I had two plates, measuring about
> 6" x 6" and a thin dielectric. I charged this plate capacitor up to about
> 15kVDC using a small
> EMCO DC-DC High Voltage Power supply. I completely dissassembled the
> capacitor, removed the dielectric, re-assembled the capacitor, and managed
> to pull a
> nice discharge from this capacitor.
>
> 2. Now, to prove that the charge isn't stored in the dielectric and is
> actually created by the corona effect on the separation of the metal plates,
> I did the repeated the above
> experiment in a basin of mineral oil. When performed under oil, the corona
> would be minimal and no "spraying" effect would be present between the
> plates and the dielectric.
> I repeated the experiment, charged the capacitor plates to 15kVDC,
> dissassembled them, removed the dielectric, and then re-assembled them. I
> tried discharging this
> capacitor now, and there was absolutely nothing. I repeated this a few
> times and still nothing.
>
> 3. On the second version of the above experiment, I charged the plates in
> air and dis-assembled them in air. I then put the capacitor together under
> oil, and voila, as I guessed,
> I could pull a nice discharge from the capacitor. On the reverse, I charged
> the capacitor under oil, dissassembled it under oil, and then reassembled
> the capacitor in air. Again,
> as I guessed, there was no discharge.
>
> 4. On a final experiment, if the energy was indeed stored in the dielectric
> as the Common Misconception goes, then it should hold true no matter what
> the capacitor voltage
> was. So I repeated the experiments at a variety of low voltage (100VDC,
> 200VDC . . . to about 500VDC) I charged the capacitors up. Checked the
> voltage with a multimeter
> to verify charge, and then dissassembled the capacitors. (Again, this was
> done in air) The capacitors were put together and the multimeter was used
> again to check for any voltage.
> Again, there was no voltage present in that newly assembled capacitor.
> Thinking maybe the internal impedance of the multimeter was discharging the
> capacitor before it could
> take a reading, i switched to an electrostatic meter. Again, the experiment
> was repeated, and nothing.
>
> So in light of all this, you can clearly see that the charge really isn't
> stored in the dielectric. It just so happens that when performing the
> dissectable capacitor experiment at
> high voltages that other effects are occuring causing the dielectric to be
> charged up by fringing corona fields created by the increased voltage
> potential as the capacitor plates
> are being separated.
>
> If anyone still doubts this, I challenge you to perform the experiment under
> oil. If the charge is *indeed* stored in the dielectric, you will be able
> to reproduce this
> dissectable capacitor experiment under oil.
>
>
> Dan
>
>