RE: Secondary size

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Luke" <Bluu-at-cox-dot-net> 

The rule for an arc length was understood but how that related to how
tall to make the coil was what no one explained.
John got me dialed in.

Luke Galyan
Bluu-at-cox-dot-net

-----Original Message-----
From: Tesla list [mailto:tesla-at-pupman-dot-com]
Sent: Friday, January 16, 2004 10:58 PM
To: tesla-at-pupman-dot-com
Subject: RE: Secondary size

Original poster: Thomas <tom-at-pwrcom-dot-com.au>

Original poster: "Luke" <Bluu-at-cox-dot-net>

  >Tom in the reply you just gave
  >you say pick a minimum height based on power input, to prevent
numerous
  >strikes to the primary /strike rail.
  >Wow how profound.

Glad to be of service :)

  >So what your reply is missing is the same thing all the others are
  >missing.  HOW does one do that.  Some would expect an arc of 50" to
  >travel 50" so it would be logical to make a coil taller than this so
the
  >arcs can not reach the bottom.  There were no guide lines given as to
  >what to base your statement on.

  >Its like telling someone to pick a car that will take them from las
  >Vegas to la and back on one tank of gas.  That is hard to do since
they
  >were never told anything about gas milage.

Rubbish. Many posts gave the 1.7*Sqrt(i/p pwr) = arc length, so I did
not
repeat it.

_snip_

  >Everyone else seems to have said just make it big enough.  They never
  >mentioned anything about how to figure out what big enough was.

I think you will find that many answers gave a rule of thumb. Try
reaeding
the posts again.

  >So telling me to make it tall enough to avoid strikes is good and I
knew
  >that before I ever asked.  But very few seem to actuall tell HOW they
  >figured that tall enough value out in the first place.

Again the 1.7*Sqrt(i/p pwr) was given many times, however this gives the
minimum height, you were asking about the *maximum* height. Many people
also
tried to piont out that this was not a reasonable question and show you
what
you should be asking.

I'm glad you now appear to understand, (from reading your other posts)
and
hope your coil turns out well.

Tom.