[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: Ungrounded Secondary
Original poster: "Malcolm Watts" <m.j.watts-at-massey.ac.nz>
On 17 Feb 2004, at 13:12, Tesla list wrote:
> Original poster: "Gavin Dingley" <gdingley-at-ukf-dot-net>
>
> Hi Antonio,
> am I right in thinking that connecting a top-load to either end
> results in a half-wave resonant mode, rather than the quarter-wave
> mode found with a grounded secondary that has only one top-load. As I
> understand it a standard TC secondary has a low impedance at the
> grounded base, and a high impedance at the top. In the case of a
> half-wave resonant coil, there is a high impedance either end, and a
> low impedance in the centre.
>
> I have to admit, the 1.41 factor does appear in some of my own
> experiments, and I have often wondered why it is higher in frequency
> when the coil should be resonating at half the frequency. However, you
> have cleared this up for me very elegantly!
>
> Cheers,
>
> Gavin
A side note: a grounded secondary in effect does have two toploads,
one being a giant (like the whole globe). You might view the dominant
resonant mode as being a centre-of-gravity-like phenomenon. I wonder
what sort of results one might get by running a coil with a large and
small topload and driving it proportionally towards the end with the
larger topload rather than in the middle? Something to try sometime.
Malcolm
>
> ----- Original Message -----
> From: "Tesla list" <tesla-at-pupman-dot-com>
> To: <tesla-at-pupman-dot-com>
> Sent: Monday, February 16, 2004 12:46 AM
> Subject: Re: Ungrounded Secondary
>
>
> > Original poster: "Antonio Carlos M. de Queiroz"
> <acmq-at-compuland-dot-com.br> > > Tesla list wrote: > > > Original poster:
> "Gavin Dingley" <gdingley-at-ukf-dot-net> > > > > if you connect a
> "top-load" to either end of a secondary coil, then you
> will
> > > find it will resonate at half the usual frequency, i.e. at
> half-wave > > resonance rather than quarter-wave, providing the coil
> is positioned > > horizontally (parallel to the ground). > > Humm...
> > You have the same coil with inductance L, with two terminals. Let's
> > assume that the terminals account for the greater part of the load
> > capacitance C. So we have the same coil, and two capacitances C in
> > series (assuming not much changed due to the different position). >
> This would resonate at: > f=1/(2*pi*sqrt(L*C/2)). > The frequency
> would be -greater- than the "1/4" wave frequency by a > factor of
> sqrt(2)=1.4142. >
>
>
>