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Re: Simulation of a conventional Tesla coil
Original poster: "Malcolm Watts by way of Terry Fritz <teslalist-at-qwest-dot-net>" <m.j.watts-at-massey.ac.nz>
Hi DC,
On 19 May 2003, at 11:36, Tesla list wrote:
> Original poster: "Dr. Resonance by way of Terry Fritz
<teslalist-at-qwest-dot-net>" <resonance-at-jvlnet-dot-com>
>
>
> Since you can see the wavetrain on a storage scope, and knowing the decay
> rate is directly related to circuit resistance, why not just calculate the
> current?
>
> The resistance of all circuit components can be measured (so low with large
> dia copper tubing or wire it is almost negligible) except for the higher
> resistance of the sparkgap.
>
> The sparkgap presents a problem, but by subtracting the resistance of other
> components from the total resistance you will have the resistance of the
> operating sparkgap. Total circuit resistance is directly related to the
> decrement (decay) factor of the wavetrain.
>
> Total current, I rms, in a spark oscillator circuit is:
>
> I rms = 3.14 * E * C * sqr ((N * F) / d
>
> I rms = rms current in Amperes
>
> E = Voltage on capacitor at the commencement of each wavetrain
>
> F = Freq. in Hz
>
> N = Number of sparks/second
>
> d = decrement (decay) factor of wavetrain (related to resistance)
>
>
>
>
> The logarithmic decrement factor is calculated by:
>
>
> d = 3.14 * R * sqr (C / L)
>
> d = log. decrement factor
>
> R = circuit resistance in Ohms
>
> C = capacitance in Farads
>
> L = inductance in Henries
>
>
> The above equation is solved for resistance. This gives total circuit
> resistance of an operating LC circuit.
The problem is that a circuit with a sparkgap in it exhibits a linear
decrement so you can't use the logarithmic RC formula to derive a
value for gap resistance.
Malcolm
> The actual decrement factor can be determined by viewing the waveform on a
> storage scope:
>
> d = (log n) * A1 / A3 = A2 / A4 = A m/ An
>
> d = decrement factor (typical value would be 0.25 with a total
circuit
> resistance of 5 Ohms)
>
> A1 = Amplitude of first wave (positive peak)
>
> A2 = Amplitude of first wave (negative peak)
>
> A3 = Amplitude of second wave (positive peak)
>
> A4 = Amplitude of second wave (negative peak)
>
>
> When I get my scanner running I will scan a waveform drawing which more
> clearly illustrates how the decrement value is directly measured on a
> waveform.
>
> The pos. amplitude of the first wave is the value measured from 0 to the
> first positive peak. The neg. amplitude of the first wave is the lower
> section measured from 0 to the first neg. peak.
>
> You essentially are developing a value for the actual circuit resistance
> which is directly dependent on the rate of decay of the waveform. The
> decrement is a ratio of the first peak to the second peak to the third peak,
> ... ad infinitum. This decaying value is related directly to the
> resistance.
>
> Tesla didn't have a method of directly seeing these waveforms but with
> modern storage scopes than can freeze this waveform we can take direct
> measurements of these amplitude ratios and then calculate the decrement
> factor. The measured decrement factor is then used directly into the two
> equations to find the actual total resistance of the operating LC circuit.
> After measuring the DC resistance of the circuit and subtracting this value
> (almost negligible) from the actual total resistance of the operating
> circuit we end up with the actual resistance of the operating sparkgap.
>
> Many experimenters have assumed that the resonant circuit peak discharge
> potential is E rms x 1.4. It's not. Under resonant conditions the peak
> discharge voltage of the capacitor is E rms x 2.2 (see below). This assumes
> max. spacing on the sparkgap so the cap doesn't fire early.
>
> Also, if the sparkgap is at a wide spacing, or in the case of the RSG type
> gap, and, if the capacitor recharging current is a high value, then:
>
> Ep = 1/2 * 3.14 * Emax which is equal to = 2.22 * Erms
>
> Ep = peak voltage to which capacitor is charged just before firing
>
> E max = E rms (of transformer) * 1.4 = E rms * sqr 2
>
> E = E rms voltage of transformer
>
> The above equation assumes the transformer can provide a high current to
> completely recharge the capacitor to full value before it fires.
>
> Dr. Resonance
>
> Resonance Research Corporation
> E11870 Shadylane Rd.
> Baraboo WI 53913
>
>
> -- snip --
>
> > It would be interesting to revisit spark gap voltages and currents now
> that
> > the equipment is so much better...
> >
> > Cheers,
> >
> > Terry
>
>
>