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Re: cockcroft-walton question
Original poster: "Jim Lux by way of Terry Fritz <teslalist-at-qwest-dot-net>" <jimlux-at-earthlink-dot-net>
Depends on your ripple current requirement.
The usual situation is to use equal valued C and PIV, to reduce ripple, you
increase C at the bottom stages of the stack,
so they go, e.g.
N*C, (N-1)*C,...3*C, 2*C, 1*C
In any case, the PIV rating of the rectifiers is the same for all stages..
----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Friday, May 16, 2003 7:19 PM
Subject: cockcroft-walton question
> Original poster: "Peter Lawrence by way of Terry Fritz
<teslalist-at-qwest-dot-net>" <Peter.Lawrence-at-Sun.COM>
>
> Is the following a component-efficient way to implement a Cockcroft-Walton
> voltage multiplier... (all like components have equal ratings, more in
> series as you go up through the stages) ...?
>
>
> AC in ---||--+----------+--||--||--||--+------------------+
> | | | |
> | | | |
> | | | v
> | | _ -
> | v ^ |
> | - | v
> _ | _ -
> ^ v ^ |
> | - | v
> | | _ -
> | | ^ |
> | | | v
> | | | -
> | | | |
> | | | |
> +--||--||--+--------------+--||--||--||--||--+----- HV out
> |
> |
> GND
>
>
> thanks,
> Pete Lawrence.
>
>