Re: SSTC idea

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Jim Lux by way of Terry Fritz <teslalist-at-qwest-dot-net>" <jimlux-at-earthlink-dot-net>


----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Sunday, March 16, 2003 10:03 AM
Subject: Re: SSTC idea


 > Original poster: "Yurtle Turtle by way of Terry Fritz
<teslalist-at-qwest-dot-net>" <yurtle_t-at-yahoo-dot-com>
 >
 >
 > --- Tesla list <tesla-at-pupman-dot-com> wrote:
 >  > Original poster: "Jim Lux by way of Terry Fritz
 >  > <teslalist-at-qwest-dot-net>" <jimlux-at-earthlink-dot-net>
 > <snip>
 >  >
 >  > Take some example numbers...  100 kHz resonant
 >  > frequency, 20 kV voltage, 120
 >  > bps, 1200 Watts.
 >  > First, what's the joules/bang.. 1200Watts/120
 >  > bangs/sec = 10 Joule/bang, so
 >  > now we know that the capacitor is big enough to hold
 >  > 10 Joules at 20 kV..
 >  > Using E = 1/2 * C * V^2 >>> 20 = C * 400, for V in
 >  > kV and C in uF.. C =
 >  > 20/400 = 0.05 uF.. (50 nF)
 >  > Now, figure out L to get the fres.. 628E3 =
 >  > 1E6*sqrt(1/(L*0.05))  (for L&C
 >  > in uH and uF) 1/(.628^2)/.05 = L >> L=51 uH
 >  > Now figure out peak primary current (assuming energy
 >  > in L = energy in C)..
 >  > 10 = 1/2*L*I^2 >> 20/sqrt(51E-6) = I... 2.8 kA
 >
 > Boy it's early morning (for me) but I believe that
 > should be: I=sqrt(10/((.5)(51E-6)))=626.2amps. Or did
 > I miss something?

You may be right...

10 = 1/2* L * I^2
20 = L * I^2
20/L = I^2
I = sqrt(20/L)
i = sqrt( 20/51E-6)
i = sqrt(20/51) * 1000

You're right... 626 Amps

I screwed up... I had 20/sqrt(L) not sqrt(20/L)

 >
 > Adam
 >
 > _