[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: DC charging reactor



Original poster: "D.C. Cox by way of Terry Fritz <twftesla-at-qwest-dot-net>" <resonance-at-jvlnet-dot-com>


Imagine slicing through your core with a knife. Looking at the end view of
the core you just sliced through, the will be looking at the cross sectional
area, ie, cutaway view.  If the core measures 5 inches wide x 4 inches high
then the 5 x 4 in = 20 sq. inches of cross sectional area.

This is what they are talking about --- the rectangular or square cross
section area of the core material.  The larger the cross sectional area the
more lines of magnetic flux lines that can be produced, and a higher
magnetic flux produces more power per unit area.

Dr. Resonance




----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Saturday, September 28, 2002 3:02 PM
Subject: Re: DC charging reactor


> Original poster: "Daniel Barrett by way of Terry Fritz
<twftesla-at-qwest-dot-net>" <dbarrett1-at-austin.rr-dot-com>
>
>     For mine, I used laminations from a MOT. It couldn't hurt to put an RF
> choke between the reactor and the primary circuit, but remember the
reactor
> is doing it's job at your BPS rate. So iron should work fine. YMMV...
>
>     BTW, someone recently posted some information about selecting core
size
> for a desired KVA rating. The formula relate  "core cross section" to KVA
> and the example given was 500kVA = 11 inches. My question is 11" of what?
> can someone explain this?
>     Sorry I didn't mean to hijack your thread here, it's just sort of on
the
> same subject (roll your own xfmrs)...
>
> db
>
>
> ----- Original Message -----
> From: "Tesla list" <tesla-at-pupman-dot-com>
> To: <tesla-at-pupman-dot-com>
> Sent: Saturday, September 28, 2002 2:53 PM
> Subject: DC charging reactor
>
>
> > Original poster: "Gregory Peters by way of Terry Fritz
> <twftesla-at-qwest-dot-net>" <s371034-at-student.uq.edu.au>
> >
> > Hello all,
> >
> > Regarding DC power supplies, can the charging reactor utilise an iron
> > core? I have been told that an iron core will not sufficiently block
> > RF, and that I would need to use ferrite for this purpose. Is this
> > true?
> >
> > Cheers,
> >
> > Greg.
> >
> >
> >
>
>