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*To*: tesla-at-pupman-dot-com*Subject*: Re: Secondary capacitance*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Thu, 23 May 2002 00:41:41 -0600*In-Reply-To*: <5.0.2.1.2.20020522000132.0234f300-at-hem.utfors.se>*Resent-Date*: Thu, 23 May 2002 00:41:36 -0600*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <1gpBwD.A.hLE.e8I78-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Terry Fritz" <twftesla-at-qwest-dot-net> Hi Frederick, Vs = 0.7(Vp * SQRT(Cp/Cs)) will be pretty darn close! About 1/2 the coil's power is lost in the gap which this takes into account. For a simple equation, this is as good as it gets. You may be interested in: http://hot-streamer-dot-com/TeslaCoils/MyPapers/modact/modact.html For secondary capacitance, see this program and included notes and text files... http://hot-streamer-dot-com/TeslaCoils/Programs/E-Tesla6.zip Cheers, Terry At 12:16 AM 5/22/2002 +0200, you wrote: > >Hello all, > >I'm trying to calculate the peak secondary voltage using this formula: > >Vs = Vp * SQRT(Cp/Cs) > >Vs = peak secondary voltage >Vp = peak charge voltage of tank cap >Cs = secondary capacitance (Farads) >Cp = tank capacitance (Farads) > >How do I find out the secondary capacitance (Ctot = Csec+Cterm)? >Or more exact, how do I calculate Csec (sec. coil capacitance)? >Using Bert Pool's formula for toroid capacitance, I calculated a Cterm >value of 2,503 pF. >Is the capacitance of the secondary coil significant? > >Using the first mentioned formula, my 8kV input and my 0,01 uF tank cap >gives about 715 kV peak secondary voltage which (even under ideal >conditions) seems a little high for my small coil. > >I wouldn't know what to "expect" from my coil. Here are the specs: > >Dual 4kV parallel NSTs phased for 8kV >0.01 uF MMC >Single static gap >Flat primary tapped at about 5½ turns >1200 turns secondary, 0.3 m high >6.5" by 1.8" toroid > >Sincerely, >Fredrik Holmström >

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