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*To*: tesla-at-pupman-dot-com*Subject*: Secondary capacitance*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Tue, 21 May 2002 18:52:56 -0600*Resent-Date*: Tue, 21 May 2002 19:12:31 -0600*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <nnfYoC.A.aKE.8Bv68-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "=?iso-8859-1?Q?=22Fredrik_Holmstr=F6m=22?= by way of Terry Fritz <twftesla-at-qwest-dot-net>" <osis-at-telia-dot-com> Hello all, I'm trying to calculate the peak secondary voltage using this formula: Vs = Vp * SQRT(Cp/Cs) Vs = peak secondary voltage Vp = peak charge voltage of tank cap Cs = secondary capacitance (Farads) Cp = tank capacitance (Farads) How do I find out the secondary capacitance (Ctot = Csec+Cterm)? Or more exact, how do I calculate Csec (sec. coil capacitance)? Using Bert Pool's formula for toroid capacitance, I calculated a Cterm value of 2,503 pF. Is the capacitance of the secondary coil significant? Using the first mentioned formula, my 8kV input and my 0,01 uF tank cap gives about 715 kV peak secondary voltage which (even under ideal conditions) seems a little high for my small coil. I wouldn't know what to "expect" from my coil. Here are the specs: Dual 4kV parallel NSTs phased for 8kV 0.01 uF MMC Single static gap Flat primary tapped at about 5½ turns 1200 turns secondary, 0.3 m high 6.5" by 1.8" toroid Sincerely, Fredrik Holmström

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