Re: Bleed Resistor for Homemade/Large Caps - THE FULL DESIGN NOTE S

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Black Moon by way of Terry Fritz <twftesla-at-qwest-dot-net>" <black_moons-at-hotmail-dot-com>

I here everyone speaking about 1/2 watt resistors. I must warn you that the 
standard resistor size is 1/4 watt. (aka the standard leaded resistors you 
see in circuits, just under a cm long and about 1.6 or so mm thick)


>From: "Tesla list" <tesla-at-pupman-dot-com>
>To: tesla-at-pupman-dot-com
>Subject: Re: Bleed Resistor for Homemade/Large Caps - THE FULL DESIGN
>NOTE S
>Date: Tue, 29 Oct 2002 16:45:15 -0700
>
>Original poster: "by way of Terry Fritz <twftesla-at-qwest-dot-net>" 
><Mddeming-at-aol-dot-com>
>
>In a message dated 10/29/02 2:50:00 PM Eastern Standard Time, 
>tesla-at-pupman-dot-com writes:
>
>
>
>>Original poster: "Jonathan Peakall by way of Terry Fritz 
>><twftesla-at-qwest-dot-net>" <jpeakall-at-madlabs.info>
>>
>>In series, the resistors current rating will be the value of the lowest
>>resistor in the series and the resistance values add up. In parallel, the
>>current rating is added, and the resistance value added. So in this case,
>>each resistor must be rated for 5 watts.
>>
>>Regards,
>>
>>Jonathan Peakall
>
>
>Hi Jonathan,
>Let's go back to Ohm's Law 101
>I = E / R and W=ExI
>If there are 10 equal resistors in series, each one passes current of I 
>and has a voltage drop across it of E/10. Therefore the power dissipated 
>by each resistor will be I x E/10= W/10, not W. Ten equal 1/2 watt 
>resistors can dissipate 5 watts total. Current passing through each 
>resistor is I, total voltage drop across the string is E, total power is E x I.
>        I made this same mistake last month while trying to think at 3AM. ;-)
>Matt D.