Re: flat coil ?

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Chris Swinson by way of Terry Fritz <twftesla-at-qwest-dot-net>" <exxos-at-cps-games.co.uk>

Hi all,

Thanks for everyone's help. I cut the coil form out today and hope to wind
it tomorrow.  Will be interesting to see what inductance it will actually
be. I guessed it about about 8mH but could end up anything. Does anyone know
the self C of the coil ?  Most tesla programs will not work with this type
of flat coil so its hard to tell on specs of this coil :-\

Thanks,
chris



----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Wednesday, April 24, 2002 4:14 AM
Subject: Re: flat coil ?


> Original poster: "Bert Hickman by way of Terry Fritz <twftesla-at-qwest-dot-net>"
<bert.hickman-at-aquila-dot-net>
>
> Hi Chris,
>
> You can estimate the wire length and outer diameter of the spiral coil
> as follows:
>  Let:
>   Starting diameter = Do  ("inside" diameter)
>   Number of Turns   = N
>   Wire Diameter     = Dw
>
>  Then:
>   Total Length of wire  = Pi[(N+1)*D + Dw*(N^2 + N)]
>   Outer spiral Diameter = Do+(2*N*Dw)
>
> Plugging in Do = 0, N = 500, and Dw = 1.6mm and converting units, I end
> up with a coil about 5.25 feet in diameter, requiring over 4100 feet of
> wire.
>
> Working backwards, a 4 foot diameter coil would require about 381 turns
> and 2400 feet of wire.
>
> Hope this helps!
>
> -- Bert --
> --
> Bert Hickman
> Stoneridge Engineering
> Coins Shrunk Electromagnetically!
> http://www.teslamania-dot-com
>
> Tesla list wrote:
> >
> > Original poster: "Chris Swinson by way of Terry Fritz
> <twftesla-at-qwest-dot-net>" <exxos-at-cps-games.co.uk>
> >
> > Hey all,
> >
> > I am just about to build a large flat secondary coil.  The wire length
will
> > be 2000ft, the wire dia is 1.6mm. I *think* this will be 500 turns at
about
> > 4foot dia.  Anyone got any ideas if that sounds about righ before I wind
the
> > thing ?
> >
> > Thanks,
> > chris
>
>
>
>