Re: Theoretically, Cltr/Cres = pi/2

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Ed Phillips by way of Terry Fritz <twftesla-at-qwest-dot-net>" <evp-at-pacbell-dot-net>

Tesla list wrote:
> 
> Original poster: "Peter Lawrence by way of Terry Fritz
<twftesla-at-qwest-dot-net>" <Peter.Lawrence-at-Sun-dot-com>
> 
> does anyone believe "L-sec" and "k" are "independent of manufacturer"
> so that tables can be published for typical NSTs
>         6-30
>         7.5-30
>         9-30,  9-60
>         12-30, 12-60
>         15-30, 15-60
> 
> the curious duffer,
> -Peter Lawrence.

	IF the open circuit voltage and short circuit current equal to the
ratings, the leakage inductance referred to the secondaries will be very
close to the same.  The leakage REACTANCE will be the open circuit
voltage divided by the short circuit current IN AMPS.  For a 60 cycle
transformer the inductance will be the reactance/377.  So, here's what
the results would be:

  "6-30"   X=6000/0.03 = 200,000 ohms   L=200,000/3677 = 530 henries

"7.5-30"   X=7500/0.03 = 250,000 ohms   L=250,000/3677 = 663 henries

  "9-30"   X=9000/0.03 = 200,000 ohms   L=200,000/3677 = 530 henries

  "9-60"   X=9000/0.06 = 150,000 ohms   L=150,000/3677 = 398 henries

 "12-30"   X=12000/0.03 = 400,000 ohms   L=400,000/3677 = 1061 henries

 "12-60"   X=12000/0.06 = 200,000 ohms   L=200,000/3677 = 530 henries

 "15-30"   X=12000/0.03 = 500,000 ohms   L=500,000/3677 = 1326 henries

 "16-60"   X=12000/0.06 = 200,000 ohms   L=200,000/3677 = 530 henries

In reality, the core properties and effects of flux density may differ,
resulting in some difference in the inductance, which is only an
approximation at best.  "Plenty good enough for government work".

	I don't think the concept of coupling factor (k) is of much value here.

Ed