Re: [Fwd: Spark gap not firing]

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Terry Fritz" <twftesla-at-uswest-dot-net>

Hi Luc,

That should be fine.  It will really knock down the Fo and it will
definitly knock out the really high frequncy burst when the gap starts to
conduct.  Fc is 50kHz in your case.

Cheers,

	Terry


At 07:21 PM 2/10/2001 -0500, you wrote:
>Hi Ed, Terry, list
>
>Tx guy for your help. Just to verified if I understand well: If I want a 
>cutoff frequency of 50
>KHz and I use a resistance of 2 Kohms I need a cap of 1.59 nF. If I use less 
>resistance and
>more capacitance for the same value in the equation is the curve: frequency 
>to db attenuation
>will be stepper  ? If my coil have a resonant F of 100 KHz is this filter 
>good or I'll need a
>cutoff F lower .
>
>Luc Benard
>
>Tesla list wrote:
>
>> Original poster: "Ed Phillips by way of Terry Fritz <twftesla-at-uswest-dot-net>" 
><evp-at-pacbell-dot-net>
>>
>>
>>
>>         The expression for the half-power cutoff frequency of a low pass RC
>> filter is simply
>>
>>         Fc = 1/(2*pi*R*C)
>>
>> where Fc is in Hz at which the output voltage/input voltage ratio is
>> 0.707 [1/sqrt(2)] , R is in ohms, and C is in farads.  This applies to
>> the simplified case of a filter between a zero-impedance source and an
>> infinite impedance load. In the case of such a filter inserted between a
>> TC primary circuit and a transformer, things may not be quite so simple.
>>
>> Ed
>