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*To*: tesla-at-pupman-dot-com*Subject*: Re: Wire Length*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Sat, 28 Apr 2001 19:27:20 -0600*In-Reply-To*: <000801c0d043$6a5649c0$5e368318-at-mw.mediaone-dot-net>*Resent-Date*: Sat, 28 Apr 2001 19:42:02 -0600*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <jpykX.A.TjG.nF366-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Terry Fritz" <twftesla-at-uswest-dot-net> Hi Jason, Electrically, the length does not matter. The old wire length for a certain frequency stuff has been shown to be a myth. Most people are winding with about 800-1200 turns these days. Of course, the length of wire on a secondary is: wl = pi x n x d wl = wire length pi = 3.14159 n = number of turns d = diameter of secondary where the same units of measure are used throughout. That is not the "exact" formula since it is about a foot or two short but close enough for practical purposes. The real formula needs the wire stretched very slightly as: wl(actual) = SQRT(wl^2 + (length of secondary)^2) Cheers, Terry At 08:29 PM 4/28/2001 -0400, you wrote: > > Hey, > > Anyone know a formula to calculate the needed length of wire for a secondary > coil? > > -Jason

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