Re: Geek Group Caps, calcualting for a MMC Oops!

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "by way of Terry Fritz <twftesla-at-uswest-dot-net>" <Mddeming-at-aol-dot-com>

In a message dated 4/19/01 8:48:52 PM Eastern Daylight Time, tesla-at-pupman-dot-com 
writes: 




>
> Original poster: "by way of Terry Fritz <twftesla-at-uswest-dot-net>" < 
> Mddeming-at-aol-dot-com> 
>
> In a message dated 4/19/01 10:55:36 AM Eastern Daylight Time, 
> tesla-at-pupman-dot-com writes: 
>
>
> > 
> > Howdy, 
> > 
> > I could use a clue. Is this how ganging up caps works? 
> > 
> > Assuming the GG caps (.15 uf, 2kv) 
> > 
> > 2* = .075uf/ 4kv,  3* = .0375uf/6kv,  4*= .0187/8kv 
> > 
> > What I mostly want to know is if I have the voltage ratings right. 
> > 
> > Thanks for bearing with the mathematically challanged. 
> > 
> > Jonathan 
>
>
>
> Almost, 
> 1=0.15-at-2kv, 2=0.075-at-4kv, 3= 0.05-at-6kv, 4=0.0375-at-8kv 5=0.03-at-10kv, 
> 6=0.025-at-12kv, 
> ... 10=.015-at-20kv....C(string)=C(of one)/N -at-N kv. 
> Matt D. 


Better make that C(of one)/N -at- 2Nkv. Sorry for the finger slip. MDD