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it has been said that a leading current would be a no no? why is this? i
would think that in a very much higher then resonant cap, the leading
current would help to charge the tank at a higher rate?
being the voltage is steady, the higher cap value charges at a rate
relating to current so if a leading factor was introduced, wouldn't this
help charge the large cap with a 120bps gap?
am i sticking the jugular out again? marc