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Re: Effects of the size of toroids
Tesla List wrote:
>
> Original Poster: "Neal Whitaker" <NDWhitaker-at-Worldnet.att-dot-net>
>...
> However I started playing around with numbers
> and found
> that a 8" x 11.035" has the same capacitance as well as a 1" x 41.3"
> (both 20 pF) (these were extremes in both directions)
>
> By applying the formula for area of a torus (4pi^2Rr) to the toroid I
> found the following
> the 8" x 11.035" has surface area of 871.288 in^2
> while 1" x 41.3" has a surface area of 407.61 in^2
>
> This is a 113% increase in surface area. The 3" x 20" is around 500
> in^2
>
> My question is as follows: How does the surface area or size of the
> toroid affect the ouput of the coil.?
The capacitance affects the dynamics of the coil operation (or the
resonance frequency, if you like). The shape of the terminal affects
the maximum voltage that it can sustain before breakdown of the
surrounding air, due to the intensity of the electric field.
A ball (a toroid with the two diameters identical) results in the
maximum voltage, and a thin toroid in the minimum. The surface
area doesn't affect significantly the operation of the system, as
the charges locate themselves always at the outer border of the
toroid, more and more concentrated as the diameter of the "tube"
becomes smaller.
About this, do someone know a formula for the maximum electric
field at the surface of a toroid, given the voltage? (I asked this
question some time ago, but didn't get any pointer that I could
find). Not difficult to discover with an electrostatic simulator,
but the geometry seems simple enough for a closed formula.
Antonio Carlos M. de Queiroz