Re: Voltage determination

[Terry Fritz <twftesla-at-uswest-dot-net>]

At 11:35 AM 7/27/00 +0200, you wrote:
>----- Original Message -----
>From: "Tesla list" <tesla-at-pupman-dot-com>
>To: <tesla-at-pupman-dot-com>
>Sent: Thursday, July 27, 2000 2:51 AM
>Subject: Re: Voltage determination
>
>
>> Original poster: Terry Fritz <twftesla-at-uswest-dot-net>
>>
>> Hi Tom,
>>
>> The "Vs = Vp sqrt(Ls/Lp)" is a very standard Tesla coil equation.
>> Personally, I divide the Vs voltage by 1/2 to allow for the source and
>load
>> impedance of a real coil.  Thus, I use:
>>
>> Vs = 1/2 Vp SQRT(Ls/Lp)
>>
>> This is really fairly close in most coils (Vs is a peak voltage).
>However,
>> your coil would still be 2.5 million volts which still seems too high!
>> What are Vp, Ls, and Lp for your coil?
>>
>> Cheers,
>>
>> Terry
>
>Vp is 7300 V,Ls is 30 mH and Lp is 39 µH.My cap is a MMC with 15 nF
>

Vp = 7300
Ls = 0.030
Lp = 0.000039
sqrt(Ls/Lp) = 27.735
Vp x 27.735 = 202466

So "I" get 202kV, not 5 million volts!?!  Using my 1/2 rule that would be
101kV.  Much more beliveable numbers.

Terry

>>
>> At 09:34 AM 7/26/00 +0200, you wrote:
>> >John
>> >When I take your formula,I have over 5 million Volt.A little much for a
>> >6"x25" secondary,don't you think ?
>> >
>> >Tom