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Re: more rsg/cap queries
Hi Richie,
I've got a question for you (or anyone),
You mentioned that "if the gap fails to fire....the voltage will be 41%
higher" (see below).
Why will it be 41% higher? I know the voltage will continue to rise, but (in
laymans terms) as the next electrode "whistles" by, why wouldn't that
electrode dictate the firing voltage if it fired? Are you talking about a
specific gap? The gap itself ultimately determines the firing voltage, based
on alignment frequency, charge, and gap spacing.
Bart
Tesla List wrote:
> Original Poster: "R.E.Burnett" <R.E.Burnett-at-newcastle.ac.uk>
>
> > Original Poster: Robin Copini <rcopini-at-merlin-dot-net.au>
> >
> > what happens if, while the cap is charging on the down side of the
> > incoming AC waveform,(or the upside of the reverse) - and does not
> > discharge due to insufficient voltage across the presented gap - it is
> > presented with the now 'reversed' polarity of the AC waveform after
> > having gone through it's zero point? I mean, all stupid questions
> > allowed of course, it is seems to me that for at least a very short time
> > the cap and transformer are presenting opposing polarities. Is this
> > right? if it is what happens during this time?
> >
> > Regards
> >
> > Robin Copini,
> > Adelaide - South Australia.
> >
> >
> If the gap fails to fire on one cycle, the capacitor voltage will swing
> back to a higher voltage on the next half cycle. The energy used to
> charge it in the positive direction is not lost, it just results in a
> bigger negative bang, next time the gap fires. I think the voltage is
> 41% higher. since E=0.5xCxVxV the energy for this bang is double.
>
> Remember the charging circuit is resonant, think of a childs swing, or a
> pendulum.
>
> Richie.