Re: Caps in series

In a message dated 7/1/99 8:27:19 AM Mid-Atlantic Daylight Time, 
tesla-at-pupman-dot-com writes:

<< Subj:	Caps in series
 Date:	7/1/99 8:27:19 AM Mid-Atlantic Daylight Time
 From:	tesla-at-pupman-dot-com (Tesla List)
 To:	tesla-at-pupman-dot-com
 Original Poster: Erthwin-at-aol-dot-com 
 I know that if I wire two 5Kv .01uF capacitors in series I'll end up with a 
 10Kv .005uF cap but what happens when I put in a third capacitor that has 
 same ratings? does the uF rating drop by half again (15Kv .0025) or is it 
 of the original rating now (15Kv .00333~)...or is there a completely 
 different set of equations for finding this out? I ask this because I'm 
 planning on looking for some smaller voltage caps to wire in series and from 
 the other visits I've made to my local surplus I doubt I'll find anything 
 close to what I actually need so I might end up wiring a LOT of caps in 
 parallel and in series to get the values I'm looking for.
 Left, left I hadda good brain but it left...
You have it right. Caps in series are like resistors in parallel. Try the sum 
of reciprocals method: the total capacitance = the reciprocal of the 
reciprocal of C1 + C2 + C3 + C4 .........

1 / Ct = 1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 .......

The total voltage across the string equals the sum of the individual voltages.
For two caps in series you can use   C1 X C2 over C1 + C2.

Ralph Zekelman