[Prev][Next][Index][Thread]

Re: Voltage doubler (fwd)





---------- Forwarded message ----------
Date: Thu, 15 Apr 1999 11:37:13 -0700
From: "Dr. Resonance" <Dr.Resonance-at-next-wave-dot-net>
To: Tesla List <tesla-at-pupman-dot-com>
Subject: Re: Voltage doubler

TO: David

In short, you charge a capacitor via a diode with DC.  Then, on the next
cycle you charge a second capacitor in series with the first capacitor which
add to 1.414 x Erms x 2.  You are using the diodes as switches.  Charge
first cap up and then connected in series with the second (resevoir) cap
using the diodes as switches.  Good rule of them for RF design is use a
resevoir cap with a value 10 X the value of the smaller cap.  Smaller cap at
with this power level should be around 0.2 to 0.5 MFD.  For a more complex
explanation see the ARRL Radio Amateur's Handbook at any local library.

Regards,

Dr.Resonance-at-next-wave-dot-net


-----Original Message-----
From: Tesla List <tesla-at-pupman-dot-com>
To: tesla-at-pupman-dot-com <tesla-at-pupman-dot-com>
Date: Thursday, April 15, 1999 1:13 AM
Subject: Voltage doubler


>Original Poster: David Trimmell <davidt-at-pond-dot-net>
>
>Hello, I was wondering if anyone on the list, who has a good understanding
>of what is actually going on within a voltage doubling circuit, could
>explain it to me. I am, at this time, using 3 uFd capacitance in my doubler
>to feed the plates on my 833A tube coil, and can range from 0-2890 VAC into
>the doubler (safely, keeping the tubes happy). I am very interested in
>finding the optimum capacitance value for a specific power and voltage
>value. I understand the principle of the halfwave voltage doubler circuit,
>but would like to know if the voltage is truly doubled, and how I can find
>the best value for the capacitance? I suspect that the higher the value for
>C, then the greater power available, but I need to find that optimum value
;-)
>
>Thanks for any assistance,
>
>David Trimmell
>
>PS. I am using the doubling circuit that Dave Sharpe and John Freau have
>used on their tube coils, i.e., cathode grounded on the diode.
>