Re: Double dielectric capacitors?

To: tesla-at-pupman-dot-com
Subject: Re: Double dielectric capacitors?
From: "mike" <mike-at-gmx-dot-com> (by way of Terry Fritz <terryf-at-verinet-dot-com>)
Date: Sat, 10 Oct 1998 11:20:59 -0600
Approved: terryf-at-verinet-dot-com



 According to the "Standard Handbook for Electrical Engineers", the formula
for C with two dielectrics in series is:

    C = k0 kA kB A / (kA tB) + (kB tA)

It also states that: "When different dielectrics appear in series, the
greater stress with AC fields is on the material having the lower
dielectric constant. This material will frequently break down first unless
its dielectric strength is much higher."

EA / EB = kB / kA


EA = V / tA + Tb kA / KB

Hope this helps,

- Mike



>  - material A, thickness tA, dielectric constant kA, dielectrict strength
vA
>  - material B, thickness tB, dielectric constant kB, dielectrict strength
vB
>  
>  what is going to be the resulting dielectric constant? And the
dielectric
>  strength?