# Re: How to rise the secondary? (fwd)

```

---------- Forwarded message ----------
Date: Sat, 18 Jul 1998 07:13:27 +0000
From: "John H. Couture" <couturejh-at-worldnet.att-dot-net>
To: Tesla List <tesla-at-pupman-dot-com>
Subject: Re: How to rise the secondary?

Antonio -

In your teslasim program example below what input watts are you using to
obtain the 313KV secondary voltage. Wouldn't changing this input wattage
change the secondary voltage? With the JHCTES program the secondary voltage
is affected by the amount of input wattage.

John Couture

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

At 12:31 AM 7/4/98 -0500, you wrote:
>----------
>From:  Antonio Carlos M. de Queiroz [SMTP:acmq-at-compuland-dot-com.br]
>Sent:  Friday, July 03, 1998 12:47 AM
>To:  Tesla List
>Subject:  Re: How to rise the secondary?
>
~~~~~~~~~~~~~~~  big snip

>An example:
>Simulated in my teslasim program (ftp://ftp.coe.ufrj.br/pub/acmq/teslasim.zip)
>Primary inductance L1: 0.1 mH
>Primary capacitance C1: 10 nF
>Secondary inductance L2: 100 mH
>Secondary capacitance C2 (self+top): 10 pF
>Coupling coefficient k=0.2
>Primary capacitor voltage V1: 10 kV
>All resistances set to zero, an ideal case for simplicity.
>This results in resonance at 159 kHz.
>
>k=0.2 is a particularly bad choice, with zeros of the secondary voltage
>coinciding with the peaks of the beat envelope.
>The maximum secondary voltage occurs at the peak of the 5th half cycle:
>Time of the peak: 13.9 us
>Secondary voltage V2peak: 313 kV
>Primary voltage: ~0 V (the program computes -20 V, but this can be
numerical noise)
>Secondary current: 0 A
>Primary current I1remaining: 14.1 A
>
>This corresponds to:
>
>Initial primary energy (0.5*C1*V1^2) = 0.5 J
>Secondary energy at the peak of the secondary voltage: E2 = 0.5*C2*V2peak^2
= 0.490 J
>Primary energy left at the same instant: E1 = 0.010 J
>Total energy at this instant: Et = E1 + E2 = 0.5 J (just to check)
>In this example, 98% of the energy is transferred. The small loss is
entirely due to
>the suboptimal coupling coefficient. Higher losses can occur with lower
coupling
>coefficients, but assuming that most coils use k<0.2, and this is a