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Who or what is Q




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From:  W Y Liu [SMTP:eenwyl-at-sun.leeds.ac.uk]
Sent:  Saturday, August 22, 1998 10:06 PM
To:  tesla-at-pupman-dot-com
Subject:  Re: Who or what is Q


Given that there is an oscillator of Q=100, the time constant
of the turn-on transient for this oscillator is roughly 100 
cycles of the oscillation frequency in length.


Louis
(non-coiler)

> From tesla-request-at-pupman-dot-com Sat Aug 22 22:40 BST 1998
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> ----------
> From:  RWB355-at-aol-dot-com [SMTP:RWB355-at-aol-dot-com]
> Sent:  Saturday, August 22, 1998 12:41 PM
> To:  fwd
> Subject:  Who or what is Q
> 
> Hi all,
> 
> There has been a lot of talk about "Q". Let me see if I can shed some light on
>  who or what Q is. 
> NO Q isnīt that dude from Star Trek.
> Q is a ratio factor that describes the behavior of a circuit. Without running
>  a lot of math:
> 
>        w(omega) * L
> Q=   ------------------ Lets simplify this as w=2* pi*F
>             R. 
>           2*pi*f*L
> =     ------------------
>              R
> 
> So this means Q is the ratio of inductive reactance to (ohmical) resistance.
>  The higer your Q is (Read: high inductive part, low resistance part) the
>  "sharper" your resonance curve is (if you plot it). A small Q (e.g.=1) would
>  give you a lazy curve like an upside down "U". A high Q (e.g. 1000) on the
>  other hand would give you a fast rise / fast drop curve with a real needle
>  point as the peak value. The "cut-off", if you will, is much harder. Taking
>  this and the transformer laws into account you can now  see why a high Q coil
>  will be able to produce a longer and fatter spark. This also shows why you
>  canīt (like I first did, growl!!) just go to wire length calculations for 
your
>  secondary. A small coil (high h/d ratio) will have a different inductance 
than
>  a big coil (low h/d ratio) wound with the same length of wire. The big coil
>  (using thicker wire) has a better Q, so it will perform better. Of course you
>  need to adjust the input power for the bigger coil. The bigger coil will need
>  more juice. But if you connect your big ps to the smaller coil you will get
>  less output bang for your money. What I find very intersting is that the
>  optimal h/d ratio turns out to be Pi (3.14159 etc), but it does make sense if
>  you look at several ac equations.
> 
> coiler greetings,
> Reinhard
>  
> 
>