Re: 60 vs. 30 ma

• To: "'Tesla List'" <tesla-at-poodle.pupman-dot-com>
• Subject: Re: 60 vs. 30 ma
• From: Tesla List <tesla-at-stic-dot-net>
• Date: Thu, 26 Jun 1997 15:23:20 -0500
• Approved: tesla-at-stic-dot-net

From: 	Peter Electric[SMTP:elekessy-at-macquarie.matra-dot-com.au]
Sent: 	Thursday, June 26, 1997 5:29 AM
To: 	Tesla List
Subject: 	Re: 60 vs. 30 ma

Tesla List wrote:
> 
> From:   Rick Holland[SMTP:rickh-at-ghg-dot-net]
> Sent:   Monday, June 23, 1997 11:13 PM
> To:     Tesla List
> Subject:        Re: 60 vs. 30 ma
> 
> --
> Forget rivers. We're talking electronics. The formula for attaining 63%
> of maximum charge (ie. applied VOLTAGE) in terms of time is R*C. The
> number of time constants required to approximate full charge is 3. In
> order to decrease the amount of time necessary to charge the capacitor,
> you must decrease R or C or increase voltage. In the event you increase
> voltage, the resultant 63% will be that fraction of a higher voltage.
> Increasing current and leaving all other factors even will not decrease
> charge time or increase charge per time unit.
> 
>       Rick Holland
> 
>       The Answer is 42

How can you possibly increase current without decreasing R? The current
from a Xformer is limited by the R of the windings. If this is decreased
the the product of R and C will indeed decrease so your cap will charge
and fire more often.

Cheers,

Peter E

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