Re: Doorknob Caps
Subject: Re: Doorknob Caps
Date: Wed, 11 Jun 1997 19:48:00 +0000
From: "John H. Couture" <couturejh-at-worldnet.att-dot-net>
To: Tesla List <tesla-at-pupman-dot-com>
At 05:32 AM 6/11/97 +0000, you wrote:
>Subject: Re: Doorknob Caps
> Date: Tue, 10 Jun 1997 22:51:08 +0500
> From: "Alfred A. Skrocki" <alfred.skrocki-at-cybernetworking-dot-com>
> To: Tesla List <tesla-at-pupman-dot-com>
>On Tue, 10 Jun 1997 05:41:49 +0000 wrote;
>> Power factor losses? Do you mean high power factor means high losses?
>> How do you determine losses using the power factor?
>When you apply R.F. do a dielectric as in a capacitor, the dielectric
>will absorb a percentage of the R.F. and dissipate it as heat and
>this dissipation is inversely proportional to the power factor of the
>dielectric. For example Mica has about the lowest power factor
>(0.0001) of all the available dielectrics and it consequently has the
>lowest losses from R.F. absorption, next to Mica is Teflon with a
>power factor of 0.0002 and then we have Polyethylene at 0.0002
>to 0.0005. a really bad dielectric would be Cellulose Acetate with a
>power factor of 0.01 to 0.1 it will melt down rapidly under R.F. due
>to it's high absorption of R.F.
>> The last I heard losses were resistive in capacitors or inductors.
>I would think the resistive losses in a capacitor is going to be
>insignificant, the reactance losses are another story, remember
>were dealing with A.C. Your also forgetting that inductors also have
I received your answer before I got my posted question on the List?
Dielectric dissipation is resistive loss (heat)
RF absorption causes resistive loss
Melt down requires heat (resistive loss)
Resistive losses in capacitors are always significant in Tesla coils
Reactance losses - what do you mean?
All losses in reactors are resistive
Hysteresis losses are resistive losses
Note that dissipation loss and dissipation factor are two
The dissipation (resistive loss) in a capacitor is DIRECTLY
proportional to the power factor. The dissipation FACTOR is
inversly proportional to the power factor.
Watt loss = VA cos (a) cos (a) = power factor
Watt loss = resistive loss R PF = W/VA = R/VA
If the power factor (decimal 0 to 1) increases the wattage
(resistive losses) increase. If the angle (a) (0 to 90)
increases the cosine and the resistive losses will decrease.
Your comments are welcomed.